package com.wc.codeforces.思维.Adjust_The_Presentation_Easy_Version;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.HashSet;
import java.util.Set;
import java.util.StringTokenizer;

/**
 * @Author congge
 * @Date 2024/10/6 18:22
 * @description https://codeforces.com/contest/2021/problem/C1
 */
public class Main {
    /**
     * 思路：<p>
     * 双指针，因为前面的人可以随便放位置,那就属于前面的人随便用, + 当前的人就OK
     */
    static FastReader sc = new FastReader();
    static PrintWriter out = new PrintWriter(System.out);
    static int N = 200010;
    static int[] a = new int[N], b = new int[N];
    static Set<Integer> set = new HashSet<>();
    static int n, m, q;

    public static void main(String[] args) {
        int T = sc.nextInt();
        while (T-- > 0) {
            n = sc.nextInt();
            m = sc.nextInt();
            q = sc.nextInt();
            for (int i = 0; i < n; i++) a[i] = sc.nextInt();
            for (int i = 0; i < m; i++) b[i] = sc.nextInt();
            int i = 0, j = 0;
            a[n] = 0;
            while (j < m) {
                if (a[i] == b[j]) {
                    set.add(a[i]);
                    i++;
                    j++;
                    continue;
                }
                if (set.contains(b[j])) j++;
                else break;
            }
            if (j < m) out.println("TIDAK");
            else out.println("YA");
            set.clear();
        }
        out.flush();
    }
}

class FastReader {
    StringTokenizer st;
    BufferedReader br;

    FastReader() {
        br = new BufferedReader(new InputStreamReader(System.in));
    }

    String next() {
        while (st == null || !st.hasMoreElements()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }

    int nextInt() {
        return Integer.parseInt(next());
    }

    String nextLine() {
        String s = "";
        try {
            s = br.readLine();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return s;
    }

    long nextLong() {
        return Long.parseLong(next());
    }

    double nextDouble() {
        return Double.parseDouble(next());
    }

    // 是否由下一个
    boolean hasNext() {
        while (st == null || !st.hasMoreTokens()) {
            try {
                String line = br.readLine();
                if (line == null)
                    return false;
                st = new StringTokenizer(line);
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
        }
        return true;
    }
}
